Question

Solve the above question​

Answer 1

Answer:

$x {}^{2} - 41x + 1 = 0$

Step-by-step explanation:

$x {}^{2} + 1 = 41x$

at last we will get a equation.

Answer 2

Answer:

20 or 1/20

Step-by-step explanation:

Lets convert the fraction into improper fraction

2 01 = 20 (2)+1 = 41

20 20 20

x + 1/x = 41/20

Take LCM ( LCM = x )

x^2+1 = 41

x 20

=> 20 ( x^2 + 1 ) = 41 ( x )

=> 20x^2 + 20 = 41x

=> 20x^2 - 41x + 20 = 0

=> 20x^2 - 40x - 1x + 20 = 0

=> 20x( x - 20 ) - 1 ( x - 20 ) =0

=> ( x - 20 ) ( 20x - 1) = 0

Hence,

x - 20 = 0 OR 20x - 1 = 0

x = 20 OR x = 1 /20