Question

solve the above question..​

Answer 1

Answer:

proved

Step-by-step explanation:

given : AB = EF, BC = DE, AB⊥BD , FE⊥CE

to prove : ΔABD≅ΔFBC

Proof : as, BC = DE (given)____ (i)

adding CD to both sides of eq. (i)

BC + CD = DE + CD

BD = CE _______________(ii)

now in ΔABD and ΔFEC,

AB = FE (given)

BD = CE (from eq. (i))

∠ABD = ∠FEC (given ⊥)

therefore, ΔABD ≅ ΔFBC

HENCE PROVED

Answer 2

Answer:

Yahi. 100.points.ka.puchho.gadhe