solve the above question
Attachments:

Answers
Answered by
2
Answer:
let the numerator x and the denominator y
numerator is increased by 20%
so x+(20x/100)
=6x/5
denominator decreased by 10%
=y-10y/100
=9y/100
so fraction is(6x/5)/(9x/100)
=6x/5*100/9y
=120x/9y
=40x/3y
=
=16/21
so the original fraction is
x/y=16/21*3/40
=4/70
=2/35
Answered by
66
Let the fraction be .
Then from the given condition :-
(x+10% of x) / (y - 10% of y) = 16/21
⇒
⇒
⇒
Similar questions