Question

solve the above question ​

Answer 1

Answer:

let the numerator x and the denominator y

numerator is increased by 20%

so x+(20x/100)

=6x/5

denominator decreased by 10%

=y-10y/100

=9y/100

so fraction is(6x/5)/(9x/100)

=6x/5*100/9y

=120x/9y

=40x/3y

=

=16/21

so the original fraction is

x/y=16/21*3/40

=4/70

=2/35

Answer 2

$\mathcal{ANSWER}$

$\boxed{\bold{\frac{4}{7}}}$

$\mathcal{SOLUTION}$

Let the fraction be  $\bold{\frac{x}{y}}$ .

Then from the given condition :-

(x+10% of x) / (y - 10% of y) = 16/21

⇒   $\bold{\frac{x + \frac{x}{5} }{y - \frac{y}{10} } = \frac{16}{21}}$

⇒   $\bold{\frac{\frac{6x}{5} }{\frac{9y}{10} } = \frac{16}{21} }$

⇒    $\bold{\frac{x}{y} = \frac{16}{21} \times \frac{9}{10} \times \frac{5}{6} = \frac{4}{7}}$

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