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x = a(θ + sinθ) and y = a(1 - cosθ)
=> dx/dθ = a(1 + cosθ) and dy/dθ = asinθ
=> dy/dx
= (dy/dθ) / (dx/dθ)
= asinθ / a(1 + cosθ)
= 2sin(θ/2)cos(θ/2) / 2cos^2 (θ/2)
= tan(θ/2).
hope it helps you.....mark my answer as brailiest answer if you like......
=> dx/dθ = a(1 + cosθ) and dy/dθ = asinθ
=> dy/dx
= (dy/dθ) / (dx/dθ)
= asinθ / a(1 + cosθ)
= 2sin(θ/2)cos(θ/2) / 2cos^2 (θ/2)
= tan(θ/2).
hope it helps you.....mark my answer as brailiest answer if you like......
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