Question

solve the above question ​

Answer 1

let the height of given tree = AC
it broke from point = B
and touches the ground at point = D
angleC= 90
So AB = BD (broken branch)
now in right angled BCD
BC/CD = tan30
BC/8 = 1/√3
BC =8/√3
again in triangle BCD
CD/ BD = COS30
8/BD= √3/2
BD = 16/√3
AB = BD
so height of tree = AB + BC
8√3+ 16√3 = 24√3
= 13.85 m