solve the above question
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Answered by
1
Heya
_______________________________
1 - Sin 2x = ( Cos x - Sin x )²
=>
integration of √( 1 - Sin2x ) dx is =
integration of √ ( Cos x - Sin x )² dx
=>
Integration of { Cos x - Sin x }dx
=>
Sin x + Cos x
_______________________________
1 - Sin 2x = ( Cos x - Sin x )²
=>
integration of √( 1 - Sin2x ) dx is =
integration of √ ( Cos x - Sin x )² dx
=>
Integration of { Cos x - Sin x }dx
=>
Sin x + Cos x
shivendrass:
thanks very much
Answered by
1
integration of √(1- sin 2 x ) dc
( cos x - sin x)2 dx
{ cos x - sin x } dx
sin x + cos x
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