Solve the above question.
•it should be neat & clean ☺
•wrong or unnecessary solutions will be reported !!
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Answered by
12
Heya User,
--> Let's learn our childhood drawing steps :p
^_^ Tracing other's drawings that is :p
--> We use Euclid's division algorithm for finding the HCF { which is sooooo length }
--> 237 = 81 * 2 + 75
--> 81 = 75 * 1 + 6
--> 75 = 6 * 12 + 3
--> 6 = 3 * 2
Since, 3 remains at last, we get the GCD as ---> '3'
Now, our favorite part --> " Tracing back our steps "
--> 3 = 75 - 6 ( 12 )
=> 3 = 75 - ( 81 - 75 )( 12 ) = 75 ( 13 ) - 81 ( 12 )
=> 3 = [ 237 - 81(2) ] ( 13 ) - 81 ( 12 )
=> 3 = 237 ( 13 ) - 81 ( 26 ) - 81 ( 12 )
=> 3 = 237 ( 13 ) - 81 ( 38 )
=> 3 = 81 ( - 38 ) + 237 ( 13 )
Comparing this with GCD ( 81 , 237 ) = 81x + 237y :->
We Get -->
---> x = ( -38 ) || y = 13 ... We got it .. Yay !
=_= In case uh have sth to ask.. Just comment below ^_^
--> Let's learn our childhood drawing steps :p
^_^ Tracing other's drawings that is :p
--> We use Euclid's division algorithm for finding the HCF { which is sooooo length }
--> 237 = 81 * 2 + 75
--> 81 = 75 * 1 + 6
--> 75 = 6 * 12 + 3
--> 6 = 3 * 2
Since, 3 remains at last, we get the GCD as ---> '3'
Now, our favorite part --> " Tracing back our steps "
--> 3 = 75 - 6 ( 12 )
=> 3 = 75 - ( 81 - 75 )( 12 ) = 75 ( 13 ) - 81 ( 12 )
=> 3 = [ 237 - 81(2) ] ( 13 ) - 81 ( 12 )
=> 3 = 237 ( 13 ) - 81 ( 26 ) - 81 ( 12 )
=> 3 = 237 ( 13 ) - 81 ( 38 )
=> 3 = 81 ( - 38 ) + 237 ( 13 )
Comparing this with GCD ( 81 , 237 ) = 81x + 237y :->
We Get -->
---> x = ( -38 ) || y = 13 ... We got it .. Yay !
=_= In case uh have sth to ask.. Just comment below ^_^
MakutoShiedo:
aap kitne talented ho bhaiya
Answered by
4
By Euclid's Division Algorithm,
237=81(2)+(75)
81=75(1) + (6)
75=6(12)+(3)
6=3(2)+(0)
Hcf =3
Expressing it in the form of 237x+81y=HCF
3=75-6(12) { From 2nd last step}
3=75-(81-75)(12) {Substituting}
3=75-(81*12-75*12)
3=75-81*12+75*12
3=75(13)-81(12)
3=(237-81*2)(13)-81(12)
3=237(13)-81(38)
3=237(13)+81(-38) {we need an expression in the form 237x + 81y }
Therefore, x =13 , y =- 38
237=81(2)+(75)
81=75(1) + (6)
75=6(12)+(3)
6=3(2)+(0)
Hcf =3
Expressing it in the form of 237x+81y=HCF
3=75-6(12) { From 2nd last step}
3=75-(81-75)(12) {Substituting}
3=75-(81*12-75*12)
3=75-81*12+75*12
3=75(13)-81(12)
3=(237-81*2)(13)-81(12)
3=237(13)-81(38)
3=237(13)+81(-38) {we need an expression in the form 237x + 81y }
Therefore, x =13 , y =- 38
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