solve the above question related to chapter current electricity...
Answer to be given by only those students who are going to give ICSE tomorrow...thank you :)
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I) the 4 and 3 will be in series and the 8 will be their parallel so it will be
2+56/15 +6
= 8 + 3.73
= 11.73 ohms
2) 2 and 4 will be in series parallel to the 6 so it becomes
5+3+3
= 11 ohms
2+56/15 +6
= 8 + 3.73
= 11.73 ohms
2) 2 and 4 will be in series parallel to the 6 so it becomes
5+3+3
= 11 ohms
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