Question

solve the above question, try to explain it along with steps and attach to pic of the solution

Answer 1

•initial velocity of stone = u = 0m/s

•distance covered by stone to reach the ground = s = -50m (- because downward motion)

•time taken to reach the ground = t

•acceleration due to gravity = a = -g = -10m/s²

S = ut + gt²/2

-50 = 0(t) +(-10)t²/2

-50 = -5t²

t² = -50/-5

t² = 10

t = √10 s

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•In √10 second distance covered by balloon is ' S1 '

•balloon is going up with uniform velocity hence acceleration is " ZERO "

S1 = ut + at²/2

S1 = ut +(0)t²/2

S1 = ut

S1 = 5 × √10

S1 = 5√10 m
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height is the distance between the stone (which is already reached ground) and balloon .

= distance covered by stone + distance covered by balloon

= 50m + 5√10m

= (50+5√10) meters .
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