Solve the answer an elevator descends into a mine shaft at the rate of 6m/min if the descent starts from 20m above the ground level how much time will it take to reach -130m
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elevator starts from = 20 m above the ground level = +20
speed of elevator- 6 m per min
position of elevator= -130m
distance covered- +20-(-130)
=20+130=150
time taken = Distance
/time
150/6= sove it
speed of elevator- 6 m per min
position of elevator= -130m
distance covered- +20-(-130)
=20+130=150
time taken = Distance
/time
150/6= sove it
Answered by
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yes he told the correct answer
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