Question

solve the attached question​

Answer 1

Step-by-step explanation:

find the attachment

by Pythagoras theorem

PQ^2+QR^2= PR^2

25= PR^2-QR^2

25= (PR+QR)(PR-QR)

25= (25)(PR-QR)

PR-QR= 1......1

PR+QR= 25.....2

adding eq 1 and 2

2PR=26

PR= 13 cm

substituting PR in eq1

QR=12cm

now sinP=QR/PR= 12/13

cosP= PQ/PR= 5/13

tanP= QR/PQ = 12/5

hope it helps u

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