Math, asked by paavanverma9, 1 year ago

solve the attached question please

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Answered by mepriyanshuanand

Answer:

Step-by-step explanation:

Let me guess you are solving previous year questions!

So here is my Answer

Attachments:

palakhanduja: hsy its easy

palakhanduja: first take sin a common from the numerator and cos a common from denominator

palakhanduja: the numerator now becomes sin a( 1-2sin^2a)

palakhanduja: denominator becomes cos a ( 2cos^2a-1)

palakhanduja: now in the denominator 2cos^2a can be written as cosa(2(1-sin^2a)-1)

palakhanduja: then it becomes cos a( 2-2sin^2a-1)

palakhanduja: cos a (1- 2sin^2 a)

palakhanduja: in the numerator we have sina (1-2sin2a) and in denominator we have cos a (1-2sin^2a)

palakhanduja: so we cut 1- sin2a from both numerator and denominator

palakhanduja: now we are left with sina/ cos a that is equal to tan a

Answered by granthan

Sin A - 2 sin^3 A

--------------------------

2Cos^3 A - Cos A

Sin A [1 - 2 Sin^2 A]

-------------------------------

Cos A [2 Cos^2 A - 1]

Sin A [1 - 2(1 - Cos^2 A)]

--------------------------------------

Cos A [2 Cos^2 A - 1]

{As Sin^2 A = 1 - Cos^2 A}

Sin A [1 - 2 + 2 Cos^2 A]

----------------------------------

Cos A [2 Cos^2 A - 1]

Sin A [-1 + 2 Cos^2 A]

-------------------------------

Cos A [2 Cos^2 A - 1]

Sin A [2 Cos^2 A - 1]

------------------------------

Cos A [2 Cos^2 A - 1]

Sin A

----------

Cos A

=|Tan A|

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