Question

solve the both equation​

Answer 1

Step-by-step explanation:

$\frac{x - 1}{2} + \frac{x + 2}{3} - \frac{x - 3}{4} = 1 \\ \frac{6x - 6 + 4x + 8 - 3x + 9}{12} = 1 \\ \frac{6x + 4x - 3x - 6 + 8 + 9}{12} = 1 \\ \frac{7x + 11}{12} = 1 \\ 7x + 11 = 1 \times 12 \\ 7x + 11 = 12 \\ 7x = 12 - 11 \\ 7x = 1 \\ x = \frac{1}{7}$

$\frac{2x + 7}{5} - \frac{x - 3}{10} - \frac{x + 1}{15} = 0 \\ \frac{12x + 42 - 3x + 9 - 2x - 2}{30} = 0 \\ \frac{12x - 3x - 2x + 42 + 9 - 2}{30} = 0 \\ \frac{7x + 49}{30} = 0 \\ 7x + 49 = 0 \times 30 \\ 7x + 49 = 0 \\ 7x = 0 - 49 \\ 7x = - 49 \\ x = \frac{ - 49}{7} \\ x = - 7$