Math, asked by jk41338, 9 months ago

Solve the both question

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Answers

Answered by waqarsd
1

Answer:

1) x = 1

y = -3

2) x = 3

Step-by-step explanation:

 {5}^{3}  = 125 \\  \\  {10}^{ - 3}  = 0.001 \\  \\  {5}^{3}  =  {5}^{3x}  \\  \\ x = 1 \\  \\  {10}^{ - 3}  =  {10}^{y}  \\  \\ y =  - 3 \\  \\  \\ (2) \\ 3( {2}^{x}  + 1) -  {2}^{x + 2}  + 5 = 0 \\  \\ 3 \times  {2}^{x}  + 3 -  {2}^{x}  \times  {2}^{2}  + 5 = 0 \\  \\ 3 \times  {2}^{x}  + 3 - 4 \times  {2}^{x}  + 5 = 0 \\  \\ 8 -  {2}^{x}  = 0 \\  \\  {2}^{x}  = 8 \\  \\  {2}^{x}  =  {2}^{3}  \\  \\ x = 3 \\  \\

HOPE IT HELPS

Answered by 217him217
0

Step-by-step explanation:

5^3x = 125

=> 5^3x = 5³

=> 3x =3

=> x = 1.

=> (10)^y = (0.001)

=> (10)^y = 1/1000

=> (10)^y = 10^-3

=> y = -3.

=> 3*(2^x + 1) - 2^(x+2) + 5 = 0

=> 3*2^x + 3 - 2^(x+2) + 5= 0

=> 3*2^x - 2^(x+2) = -8

=> 3*2^x - 2^(x+2) = -2³

=> 2^(x+2) - 3*2^x = 2³

=> 2^x*(4-3) = 2³

=> 2^x = 2³

=> x = 3

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