Question

Solve the both questions.....as soon as possible.....​

Answer 1

Answer:

Step-by-step explanation:

equation has infinite no. of solutions

so we can apply the condition of a1/a2=b1/b2=c1/c2

2/(a-b)=3/(a+b)=7/3a+b-2

case 1

comparing a1/a2 with b1/b2

2/(a-b)=3/(a+b)

cross multiplication

2a+2b=3a-3b

2b+3b=3a-2a

5b=a

case2

comparing b1/b2 with c1/c2

3/(a+b)=7/3a+b-2

9a+3b-6=7a+7b

putting value of a

9(5b)+3b-6=7(5b)+7b

45b+3b-6=35b+7b

48b-6=42b

48b-42b=6

6b=6

b=1

now a=5(1)

a=5

hope u get it.....