Math, asked by ranabotuvenketreddy, 8 months ago

Solve the
by reducing
equations
following
them to
pair
a
of equations
pair of linear
equations 5/x+y-2/x-y=-1 and 15/x+y+7/x-y=10​

Answers

Answered by Anonymous
1

Step-by-step explanation:

Given equations are

5/x+y -2/x-y=-1 and 15/x+y + 7/x-y=10.

Let 1/x+y be a and 1/x-y be b.

Linear equations will be

5a-2b=-1...(1) and 15a+7b=10...(2)

Multiply eq(1) by 3.

15a-6b=-3...(3)

eq(3)-eq(2)

-13b=-13

b=13/13

b=1.

substitute b=1 in eq(1)

15a-6=-3

15a=3

a=3/15

a=1/5.

But 1/x+y=a and 1/x-y=b.

1/x+y=1/5

x+y=5...(4)

1/x-y=1

x-y=1...(5)

Add eq(4) and eq(5).

2x=6

x=6/2=3

substitute x=3 in eq(4).

3+y=5

y=5-3=2.

Solution

x=3 and y=2.

Answered by nehamalik985
2

Answer:

please mark as brainlist answer.

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