Math, asked by adirajput246821, 1 year ago

Solve the circle ones....

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Answered by mitajoshi11051976
1

({\frac{2}{3} )}^{ - 2}

({\frac{2}{3} )}^{ - 2} \\ ({\frac{2}{3} )}^{ - 2} \\  \\ ({\frac{2}{3} )}^{ - 2} \\ ({\frac{2}{3} )}^{ - 2} \\ ({\frac{2}{3} )}^{ - 2} \\  \\ ({\frac{2}{3} )}^{ - 2} \\ a few months ago to be honest and it was great to have the opportunity to speak to him about this and let you can use to be the same problem

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