Question

Solve the circled question

Answer 1

Answer:

x=-1/2 or x=5

Step-by-step explanation:

[8/x+3]-2=[3/2-x]

8-2x-6/x+3=3/2-x

[2-2x]*2-x=3*[x+3]

4-4x-2x+2x²=3x+9

2x²-9x-5=0

2x²-10x+x-5=0

2x[x-5]+1[x-5]=0

2x+1=0    or   x-5=0

x=-1/2    or  x=5

Answer 2

$\underline{ \underline{{ \huge{ \tt{Q}}} { \textsf{UADRATIC}} \: \: \: { \huge{ \tt{E}}}{ \textsf{QUATION :-}}}}$

$\blue{ : \longrightarrow{ \tt{ \frac{8}{x + 3} - 2 = \frac{3}{2 - x} }}} \\ \\ \tt{On \: taking \: L.C.M,} \: \: \: \: \\ \\ : \longrightarrow{ \tt{ \: \frac{8 - 2(x + 3)}{x + 3} = \frac{3}{2 - x} }} \\ \\ \\ : \longrightarrow{ \tt{ \: \frac{8 - 2x - 6}{x + 3} = \frac{3}{2 - x} }} \\ \\ \\ : \longrightarrow{ \tt{ \: \frac{2 - 2x}{x + 3} = \frac{3}{2 - x} }} \\ \\ \\ : \longrightarrow{ \tt{ \:2 - x(2 - 2x) = 3(x + 3) }} \\ \\ : \longrightarrow{ \tt{ \: 4 - 4x - 2x + 2 {x}^{2} = 3x + 9 }} \\ \\ : \longrightarrow{ \tt{ \:2 {x}^{2} - 6x + 4 = 3x + 9 }} \\ \\ : \longrightarrow{ \tt{ \:2 {x}^{2} - 6x + 4 - 3x - 9 = 0}} \\ \\ \tt{ By \: Quadratic \: method ,} \\ : \longrightarrow{ \tt{ \:2 {x}^{2} - 9x - 5 = 0}} \\ \\ : \longrightarrow{ \tt{ \:2 {x}^{2} - 10x + x - 5 = 0 }} \\ \\ : \longrightarrow{ \tt{ \:2x(x - 5) + 1(x - 5) = 0 }} \\ \\ : \longrightarrow{ \tt{ \: (2x + 1)(x - 5) = 0}} \\ \\ \\ { \tt{ : \longrightarrow 2x = - 1}} \\ \boxed{ { \tt{ : \longrightarrow x = - \frac {1}{2} }}} \\ \\ \tt{or} \\ \\ \boxed{ { \tt{ : \longrightarrow x = 5}}}$

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