solve:-
The density of air is 1.28g litre. Express in:-
(a) g cm-3
(b)kg m-3
Answers
Answered by
5
) 1000 litre = 1
m
3
Density of air = 1.28g/ 1000
m
3
=
1.28×
10
−3
gc
m
−3
(b) 1.28g =
1.28×
10
−3
kg
1
m
3
=1000litres
1litre=
1
1000
m
−3
1.28g/litre=
1.28×
10
−3
kg
1
1000
1 ltr = 1000ml = 1000cm-3, so the first answer is simple 1.28/1000 g cm-3 i.e. 1.28x10-3 g cm-3
for the second part, 1 kg = 1000g and 1m-3 = 1000 ltr, thus both numerator and denominator increased by 1000 times cancel each other and the numerical value remains the same i.e. 1.28kgm3
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m
3
Density of air = 1.28g/ 1000
m
3
=
1.28×
10
−3
gc
m
−3
(b) 1.28g =
1.28×
10
−3
kg
1
m
3
=1000litres
1litre=
1
1000
m
−3
1.28g/litre=
1.28×
10
−3
kg
1
1000
1 ltr = 1000ml = 1000cm-3, so the first answer is simple 1.28/1000 g cm-3 i.e. 1.28x10-3 g cm-3
for the second part, 1 kg = 1000g and 1m-3 = 1000 ltr, thus both numerator and denominator increased by 1000 times cancel each other and the numerical value remains the same i.e. 1.28kgm3
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