Question

Solve the determinant.......

Answer 1

$\textbf{Hey there}$!!

$\textbf{Solution}$:.

∆ = $\begin{vmatrix}1&2&3 \\ 4&5&6 \\ 7&8&9 \end{vmatrix}$

Applying $R_{3}$ ➡ $R_{3}$ - $R_{2}$

∆ = $\begin{vmatrix}1&2&3 \\ 4&2&6 \\ 3&3&3\end{vmatrix}$

Applying $R_{2}$ ➡ $R_{2}$ - $R_{3}$

∆ = $\begin{vmatrix}1&2&3 \\ 1&2&3 \\ 3&3&3\end{vmatrix}$

$R_{1}$ and $R_{2}$ are identical so the determinant is zero

Therefore

∆ = 0

#Be Brainly.

Answer 2

answer is in photo....