solve the diff equation 2(d²y/dx²)-5(dy/dx)-3y=0
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1st integrate, you will get
2(dy/dx)-5-3y^2/2+constant=0
Integrate again
2-(3×3/6)y^3+constant=0
2-(3/2)y^3+constant=0
(3/2)^y^3=2+constant
Y^3=(2+constant)(2/3)=constant
y=cube root of constant term
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