solve the differential (1+x^2) dy/dx +y = e^tan-1 x
Answers
Answered by
2
Answer:
The given differential equation may be written as
dydx+1(1+x2)⋅y=etan−1x(1+x2)
This is of the formm dydx+Py=Q , where P=1(1+x2)andQ=etan−1x(1+x2)
Thus, the given equation is linear.
IF=e∫Pdx=e∫1(1+x2)dx=etan−1x.
So, the required solution is given by
y×IF=∫∣(Q×(IF)∣dx+C,
i.e, y×etan−1x=∫{etan−1x(1+x2)×etan−1x}dx+C
=∫e2tan−1x(1+x2)dx+C
=∫e2tdt+C, where tan−1x=t
=12e2t+C=12e2tan−1x+C.
Hence, y=12etan−1x+Ce−tan−1x is the required solution.
Similar questions