solve the differential equation :(2ax+by)ydx + (ax+by)xdy =0
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FROM THE EQUATION WE GET,
2AX²DY + BY²DX + AX²DY + BY²DX = 0
=> 3AX²DY +2BY²DX = 0
3AX + 2 BY = 0
=> 3AX = -2BY
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