Math, asked by Akankshasinha6426, 1 month ago

solve the differential equation ; dy/dx=sinx .siny

Answers

Answered by Anonymous
3

Answer:

cosx

tan

2

y

=c

dy−sinxsinydx=0

⟹ dy=sinxsinydx

⟹cosec y dy=sinxdx

integating both side

⟹logtan

2

y

+logk=−cosx

c

tan

2

y

=e

−cosx

⟹e

cosx

tan

2

y

=c

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