solve the differential equation dy/dx =x^2+sin 3x
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apply product rule u will get as,
dy/dx=x²(d(sin3x)/dx) + sin3x(d(x²)/dx)
dy/dx=x²cos3x+(2x)sin3x
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if u like to further solve the answer then apply cos3x=4cos³x–3cosx and sin3x=3sinx-4sin³x formula and then u will get as,,
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dy/dx=x²4cos³x–x²3cosx+6xsinx–8xsin³x
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