Math, asked by madhuripol2035, 4 months ago

Solve the differential equation :-
dy
X
doc

y+x Sin
-
= 0
OR
Solve the differential equation :- xe +2y=x​

Answers

Answered by mohit154kumar
0

Answer:

y+x =45555866778kkkgf5yuvvgg

Answered by ravindrabansod26
6

Answer:

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Step-by-step explanation:

We have,  dx/dy +ytan x=sin x

Comparing with, standard first order linear differential equation  

dx/dy +Py=Q  

We get P=tanx and Q=sinx

Thus, integrating factor. I.F=e  

∫Pdx =e  

∫tanxdx =e  

lnsecx =secx

Therefore solution is given by,

y(I.F.)=∫Q(I.F)dx+C

⇒y(secx)=∫secxsinxdx

⇒(secx)y=∫tanxdx+C

⇒(secx)y=ln∣secx∣+C

⇒y=cosxln∣secx∣+Ccos

hope it will help you.

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