Solve the differential equation :-
dy
X
doc
뽐
y+x Sin
-
= 0
OR
Solve the differential equation :- xe +2y=x
Answers
Answered by
0
Answer:
y+x =45555866778kkkgf5yuvvgg
Answered by
6
Answer:
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Step-by-step explanation:
We have, dx/dy +ytan x=sin x
Comparing with, standard first order linear differential equation
dx/dy +Py=Q
We get P=tanx and Q=sinx
Thus, integrating factor. I.F=e
∫Pdx =e
∫tanxdx =e
lnsecx =secx
Therefore solution is given by,
y(I.F.)=∫Q(I.F)dx+C
⇒y(secx)=∫secxsinxdx
⇒(secx)y=∫tanxdx+C
⇒(secx)y=ln∣secx∣+C
⇒y=cosxln∣secx∣+Ccos
hope it will help you.
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