Question

solve the differential equation
x(dx/dy+y)=1-y​

Answer 1

Answer:

dy/dx + y = (1 - y) /x yields dy/dx + (1 + 1//x) y = 1/x. so that P = 1 + 1/x and Q = 1/x. Then the integrating factor is v(x) = e ^ {Integral P(x) dx] = e^ [x + ln x] = x e^x. ... y (xe^x) = Integral[e^x dx] = e^x +

Step-by-step explanation:

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