Math, asked by IshabhJain, 5 months ago

solve the differential equation. y=x[p+√1+p²​

Answers

Answered by pulakmath007
4

SOLUTION

TO SOLVE

The differential equation

 \sf{y = xp +  \sqrt{1 +  {p}^{2} } }

EVALUATION

Here the given differential equation is

 \sf{y = xp +  \sqrt{1 +  {p}^{2} } }

This equation is of the form

 \sf{y = xp +  f(p) }

Which is Clairaut's equation

Now for Clairaut's equation the general solution is obtained replacing p by c

Hence the required solution is

 \sf{y = cx+  \sqrt{1 +  {c}^{2} } }

Where C is constant

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. M+N(dy/dx)=0 where M and N are function of

(A) x only

(B) y only

(C) constant

(D) all of these

https://brainly.in/question/38173299

2. This type of equation is of the form dy/dx=f1(x,y)/f2(x,y)

(A) variable seprable

(B) homogeneous

(C) exact

(D) none ...

https://brainly.in/question/38173619

Similar questions