solve the differential equation ydx-3x dy= 3xydx
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It can be reduced to,
dy/dx + y/x = 3x^2 ….(i)
And, form in dy/ dx +P y =Q
Intergrating factor (IF)= e^({ 1/x dx) = e^log x = x
Multiplying eq i by IF, we get
x dy/ dx + y = 3x^3,
d (xy)= 3x^3 dx ,
Integrating both side,
xy = 3x^4/4 +c
Step-by-step explanation:
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