Question

solve the differential equation ydx-3x dy= 3xydx​

Answer 1

Answer:

It can be reduced to,

dy/dx + y/x = 3x^2 ….(i)

And, form in dy/ dx +P y =Q

Intergrating factor (IF)= e^({ 1/x dx) = e^log x = x

Multiplying eq i by IF, we get

x dy/ dx + y = 3x^3,

d (xy)= 3x^3 dx ,

Integrating both side,

xy = 3x^4/4 +c

Step-by-step explanation:

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