Question

Solve the duadratic equation
4x²-4ax+(a4-b4)=0
​

Answer 1

have a nice day

plz make me brainlist

Answer 2

$\Large\bold{\bigstar{\underline{\rm{\pink{Correct\:Question :-}}}}}$

• Solve the equation by quadratic formula: 4x2-4a2x+(a4-b4)=0 .

$\Large\bold{\bigstar{\underline{\rm{\red{Correct\:Question :-}}}}}$

$\color{Purple}\sf\large According\:to \:the \:question$

$\sf \implies \: 4 {x}^{2} - 4 {a}^{2}x + ( {a}^{4} - {b}^{4}) =0$

$\sf\large A=4\\B=-4{a}^{2}\\C= ( {a}^{4}-{b}^{4})\\D=\:?$

=(-4a²)²-4×4×(a⁴-b⁴)

=16a⁴-16a⁴+16b⁴

D=16b⁴

x=-b±√D/2a

=-(-4a²)±4a²/2×4

=4a²±4a²/8

x=4a²+4a²/8

=8a²/8

=a²

x=4a²-4a²/8

=0/8

=0