solve the eauation x⁴-4x²+8x+35=0 having given that one root is 2+√-3
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hey, just replace the `x` digit with the roots and do the problm ............
you will get it
you will get it
Anonymous:
One root is 2+√-3, one other root is 2-√-3.
Continuing with above, [x - (2+√-3)] and [x - 2-√-3)] are two factors of the given equation. Divide the given equation with expression [x-(2+√-3)]x[x-(2-√-3)]. You will get a resultant quadratic equation. Solve this quadratic equation for other roots.
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Answer:
Step-by-step explanation:
x-(2-√3i))(x-(2-√3i))=0
X-2)²-(√3i)²=0
x²+4-4x+3=0
do synthetic division for this
Then we get x²++4x+5=0
Then do -b plus or minus square root of b²-4ac/2a u get the answer
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