Question

solve the egaution and give the answer properly..!!!​

Answer 1

Answer:

x = 0 , -7

Step-by-step explanation:

Let  y = [3x - 1/2x + 3]

=> 2x + 3/ 3x -1 = 1/y

Now the equation becomes

3y - 2/y = 5

=> 3y² - 2 = 5y

=> 3y² - 5y - 2 = 0

=> 3y² - 6y + y - 2= 0

=> 3y(y -2 ) + 1(y-2) = 0

=> (3y + 1 )(y - 2) = 0

=> y = -1/3 , y = 2

But y = 3x - 1 / 2x +3

When y = -1/3                  |   When y = 2

3x -1 /2x + 3 = - 1/3         |    3x - 1/2x+3 = 2

9x - 3 = - 2x - 3               |   3x - 1 = 4x + 6

11x = 0                              |   4x - 3x  = -6 - 1

x = 0                                |    x = -7

Thus x = 0 and -7