Question

solve the eqation = 3(n-5)=21

Answer 1

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$\huge\pink{\mathfrak{Solve\:the\: equation:-}}$

3(n-5) = 21

$\huge\blue{\mathfrak{Answer:-}}$

3(n-5) = 21 [[[[ n = 12 ]]]]

$\huge\pink{\mathfrak{Solution:-}}$

3(n-5) = 21
3n - 15 = 21
3n = 21 + 15
3n = 36
n = $\frac{36}{3}$
n = 12

$\huge\blue{\mathfrak{Explanation:-}}$

3(n-5) = 21

First we should multiply 3 with "n" and "5".

3n - 15 = 21

We have to bring -15 to the right hand side. "-15" will change as "+15".

3n = 21 + 15

We will get 36 when we add 21 and 15.

3n = 36

Now We will have to find the value of n. So we should bring 3 to the Right Hand Side. Then divide 36 by 3.

n = $\frac{36}{3}$

We will get 12 when 36 is divided by 3.

n = 12

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Answer 2

Answer:

=> n = 12

Step-by-step explanation:

Given that:-

$3(n-5)=21$

As we have to find the value of the equation,

For simplifying this expression we have to use the transposition method:

We have,

=> $3(n-5)=21$

Distribute the terms,

=> $3n-15=21$

Now add both sides by $15$, we get

=> $3n-15+15=21+15$

Simplifying it further, we get

=> $3n=21+15$

Add the numbers,

=> $3n=36$

Divide both sides by $3$,

=> $n =12$

Hence, the required solution is 12.