Math, asked by soni113, 1 year ago

solve the eqation 3x^2 + 2√5x -5=0

Answers

Answered by RishabhBansal
6
Hey!!
We have

3x² + 2√5x - 5 = 0

=> 3x² + 3√5x - √5x - 5 = 0

=> 3x( x + √5) -√5( x + √5) = 0

=> (x + √5)(3x - √5) = 0


Thus x + √5 = 0
=> x = -√5

Also 3x - √5 = 0
=> x = √5/3

Hope this helps
Answered by Anonymous
3
3x² + 2√5x - 5 = 0 3x² + 3√5x - √5x - 5 = 0 3x( x + √5) -√5( x + √5) = 0 (x + √5)(3x - √5) = 0 x = -√5 or √5 / 3
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