Question

Solve the equation:-
1+3+5+............+ x = 10000
please its urgent ​

Answer 1

Answer:

Step-by-step explanation:

n = n/2(2a+(n-1)d)  given a=1, d=4-1=3 & Sn = 287

287 = n/2 (2*1 +(n-1) 3)  

287*2 = n(2 + 3n - 3)

574 = 2n + 3n^2 - 3n

3n^2 -n - 574 = 0

on solving the quadratic equation using formula n= -b + sq.root(b^2 -4ac)

                                                                           -----------------------

                                                                                         2a

we get   n = 14,  -41/3  n not equal to  -41/3 due to negative nos.

n=14

Sn = n/2 (a +l)

287 = 14/2(1 +x)

574 = 14 (1+x)

574 / 14 = 1+x

41 = 1 + x

So, x = 41 - 1

     x = 40 is the solution

Answer 2

first take

x=a+(n-1)d

then

x=1+(n-1)2

x=1+2n-2

x=2n-1

then

we know that

sum of n terms is

n/2(a+N)

then

n/2(1+2n-1)

then it is n square

n square us equal to 10000

then n is equal to 100

sub n in x=2n-1

x=199