Question

solve the equation 1. (3y +2 ) (3y + 2 ) 2. (2x-5 ) (2x-5) step by step explanation​

Answer 1

Answer:

1. (3y+2)(3y+2)

$(3y + 2) ^{2}$

${(3y)}^{2} + {2}^{2} + 2(3y)(2)$

using formula

$({a + b})^{2} = {a}^{2} + {b}^{2} + 2ab$

$9 {y}^{2} + 4 + 12y$

Step-by-step explanation:

2. (2x-5)(2x-5)

it can be done using previous method

use this formula

$(x - y {)}^{2} = {x}^{2} + {y}^{2} - 2xy$

or use this method

$2x(2x - 5) - 5(2x - 5) \\ {4x}^{2} - 10x - 10x + 25 \\ {4x}^{2} - 20x + 25$

Hope it helps you !!