Solve the equation 1+4+7+⋯+x=925
omkar107:
hlw
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4
Answer:
Now, :
∴ Value of
Step-by-step explanation:
73 is the answer pakka
Answered by
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Solution:
here , the equation is 1+4+7+....+x = 925
for testing it is in A.P or not
4-1 =3 = 7-4 so, it is ne A.P
let, a be the first term of the A.P
d be the common difference of the A.P
n ne the no. of term of the A.P
S be the sum of the A.P
given, a =1
d = 3
S = 925
now, S= n/2[2a+(n-1)d]
925 = n/2[ 2*1+(n-1)*3]
3n^2 -n -1850 =0
n= (1+- √1+4*3*1850)/2*3
n= (1+- √22201)/6
n= (1+-149)/6
n=(1+149)/6 or n= (1-149)/6
n= 150/6 or n= 148/6
n= 26 or n= 24.666 , which is not possible
so, n= 26
since x is 26th term
x =a+ (n-1)d
x =1 +(26-1)*3
x= 76
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