Math, asked by ArnavChatterjee70, 4 months ago

Solve the equation


1)4(x+5)-2(x-8)=5(x-3)+20
2)2(x+1)-3(x-5)+4(x+3)=0

Answers

Answered by poojithashankar2008
3

i ) 4 ( x + 5 ) - 2 ( x - 8 ) = 5 ( x - 3 ) + 20

solution

4x + 20 - 2x + 16 = 5 ( x - 3 ) + 20

2x + 20 + 16 = 5 ( x - 3 ) + 20

2x + 36 = 5 ( x - 3 ) + 20

2x + 36 = 5x - 15 + 20

2x + 36 = 5x + 5

2x + 36 = 5x = 5

- 3x + 36 - 5x = 5

- 3x = 5x = 5

- 3x = - 31

x = - 31 / - 3

x = 31 / 3

ii ) 2 ( x + 1 ) - 3 ( x - 5 ) + 4 ( x + 3 ) = 0

solution

2x + 2 - 3 ( x - 5 ) + 4 ( x - 3 ) = 0

2x + 2 - 3x + 15 + 4 ( x - 3 ) = 0

- x + 2 + 15 + 4 ( x - 3 ) = 0

- x + 17 + 4x + 12 = 0

3x + 17 + 12 = 0

3x + 29 = 0

3x = - 29

x = - 29 / 3

x = - 29 / 3

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