Math, asked by MandiraBedi2154, 1 month ago

Solve the equation :-
1) (x+a/x-a)2 - 5(x+a/x-a) + 6 = 0

Answers

Answered by misscutie94
7

Answer:

\longmapsto \bigg(\dfrac{x + a}{x - a}\bigg)^{2} - 5\bigg(\dfrac{x + a}{x - a}\bigg) + 6 = 0

Let, \dfrac{x + a}{x - a} = y.

Hence, the given equation is,

y²- 5y + 6 = 0

y²- 3y - 2y + 6 = 0

y( y - 3 ) - 2( y - 3 ) = 0

( y - 3 ) ( y - 2 ) = 0

y - 3 = 0 ; y - 2 = 0

y = 3, y = 2

Now, if y = 3, then \dfrac{x + a}{x - 3} = 4

↦ 3(x - a) = x + a

↦ 3x - 3a = x + a

↦3x - x = 3a + a

↦ 2x = 4a

↦ x = \dfrac{4a}{2}

x = 2a

Again, of y = 2, then \dfrac{x + a}{x - a} = 2

➛ 2(x - a) = x + a

➛2x - 2a = x + a

➛2x - x = 2a + a

x = 3a

Then, required solution is x = 2a, 3a.


Rajeshwari8025: awesome ☺️
misscutie94: Thanks siso :)
MandiraBedi2154: Nice
Answered by Rajeshwari8025
3

Answer:

Then required solution is x = 2a, 3a

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