Question

solve the equation.​

Answer 1

Answer:

1/x - 1/(x-2) =3

(1(x-2)-1(x))/(x(x-2)) = 3

x-2-x = 3

x^2-2x

-2= 3(x^2 -2x)

-2 = 3x^2 -6x

3x^2 - 6x + 2 = 0

By Formula Method;

Comparing The Equation With General Form Of Equation ax^2 + bx + c = 0

a= 3

b= -6

c= 2

x = -b + √(b^2 - 4ac)

2a

x = 6 + √(36-24) (4ac = 4*3*2 =24)

4

x = 6 + √12 (√12 = √2*√2*√3)

4

x = 6 +√3/2 Or x = 6 - √3/2 Ans.

Answer 2

Answer:

Explanation:

1/x-1/(x-2)=3

⇒(x-2-x)/(x²-2x)=3

⇒-2=3x²-6x

⇒3x²-6x+2=0

By Quadratic formula,

Comparing this equation with the general equation ax²+bx+c=0

a=3,   b=-6,   c=2

x=[-b ±√(b²-4ac)]/2a

⇒x  =[6 +√(36-24)]/6 or, [6-√(36-24)]/6

       = [√(36+12)]/6 or,  [√(36-12)]/6

       =√48/6 or, √24/6

      = 4√3/6 or, 2√6/6

      =2√3/3 or, √6/3

x=2√3/3 or, √6/3

HOPE THIS HELPS U

PLS MARK AS BRAINLIEST