solve the equation 15(a-4)-2(a-9)+5(a+5)=0
Answers
Step-by-step explanation:
मराठी मध्ये शोधा
समीकरण 15 4) -2 9) आहे +5 5) = 0 निराकरण
How to solve your question
Your question is
1
5
(
−
4
)
−
2
(
−
9
)
+
5
(
+
5
)
=
0
15(a-4)-2(a-9)+5(a+5)=0
15(a−4)−2(a−9)+5(a+5)=0
Solve
1
Distribute
1
5
(
−
4
)
−
2
(
−
9
)
+
5
(
+
5
)
=
0
{\color{#c92786}{15(a-4)}}-2(a-9)+5(a+5)=0
15(a−4)−2(a−9)+5(a+5)=0
1
5
−
6
0
−
2
(
−
9
)
+
5
(
+
5
)
=
0
{\color{#c92786}{15a-60}}-2(a-9)+5(a+5)=0
15a−60−2(a−9)+5(a+5)=0
2
Distribute
again
1
5
−
6
0
−
2
(
−
9
)
+
5
(
+
5
)
=
0
15a-60{\color{#c92786}{-2(a-9)}}+5(a+5)=0
15a−60−2(a−9)+5(a+5)=0
1
5
−
6
0
−
2
+
1
8
+
5
(
+
5
)
=
0
15a-60{\color{#c92786}{-2a+18}}+5(a+5)=0
15a−60−2a+18+5(a+5)=0
3
Distribute
again
1
5
−
6
0
−
2
+
1
8
+
5
(
+
5
)
=
0
15a-60-2a+18+{\color{#c92786}{5(a+5)}}=0
15a−60−2a+18+5(a+5)=0
1
5
−
6
0
−
2
+
1
8
+
5
+
2
5
=
0
15a-60-2a+18+{\color{#c92786}{5a+25}}=0
15a−60−2a+18+5a+25=0
4
Add the numbers
1
5
−
6
0
−
2
+
1
8
+
5
+
2
5
=
0
15a{\color{#c92786}{-60}}-2a+{\color{#c92786}{18}}+5a+{\color{#c92786}{25}}=0
15a−60−2a+18+5a+25=0
1
5
−
1
7
−
2
+
5
=
0
15a{\color{#c92786}{-17}}-2a+5a=0
15a−17−2a+5a=0
5
Combine like terms
1
5
−
1
7
−
2
+
5
=
0
{\color{#c92786}{15a}}-17{\color{#c92786}{-2a}}+{\color{#c92786}{5a}}=0
15a−17−2a+5a=0
1
8
−
1
7
=
0
{\color{#c92786}{18a}}-17=0
18a−17=0
6
Add
1
7
17
17
to both sides of the equation
1
8
−
1
7
=
0
18a-17=0
18a−17=0
1
8
−
1
7
+
1
7
=
0
+
1
7
18a-17+{\color{#c92786}{17}}=0+{\color{#c92786}{17}}
18a−17+17=0+17
7
Simplify
Add the numbers
Add the numbers
again
1
8
=
1
7
18a=17
18a=17
8
Divide both sides of the equation by the same term
1
8
=
1
7
18a=17
18a=17
1
8
1
8
=
1
7
1
8
\frac{18a}{{\color{#c92786}{18}}}=\frac{17}{{\color{#c92786}{18}}}
1818a=1817
9
Simplify
Cancel terms that are in both the numerator and denominator
=
1
7
1
8
Step-by-step explanation:
15(a - 4) - 2(a - 9) + 5(a + 5) = 0
=> 15a - 60 - 2a + 18 + 5a + 25 = 0
=> 18a - 17 = 0
=> a = 17/18
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