Math, asked by bnsnsjkkaa, 8 months ago

solve the equation 16(3x-5)-10(4x-8)=40 and verify the result​

Answers

Answered by Anonymous
54

\huge\star\:\:{\orange{\underline{\pink{\mathbf{Answer}}}}}

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16(3x - 5) - 10(4x - 8) = 40

16 \times 3x - 16 \times 5 - 10 \times 4x \times + 10 \times 8 = 40 \\  = 48x - 80 - 40x  + 80 = 40 \\  = 48x - 40x - 80 + 80 = 40 \\  = (48 - 40)x + 0 = 40 \\  = 8x = 40 \\  =  \frac{8x}{8}  =  \frac{40}{8}  \\ =  x = 5

Thus,X =5 is the solution of the given equation.

\large \bold{\underline{\sf{\blue{Check}}}}

substituting x=5 in the given equation, we get L.H.S.

 = 16(3 \times 5 - 5) - 10(4 \times 5 - 8) \\  = 16(15 - 5) - 10(20 - 8) \\  = 16 \times 10 - 10 \times 12 \\  = 160 - 120 = 40

And,R.H.S. = 40

Thus,For X =5,we have L.H.S.=R.H.S

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Answered by Anonymous
28

\huge\underline\bold{Question}

  • solve the following equation ..!

(i) 16(3x-5) - 10(4x-8) = 40

\huge\underline\bold{Answer}

\hookrightarrow 16(3x-5) - 10(4x-8) = 40

\hookrightarrow\:48x\:-80\:-40x\:+80\:=\:40

\hookrightarrow\:48x\:-40x\:=\:40\:+80\:-80

\hookrightarrow\:8x\:=\:40

\hookrightarrow\:x\:=\: \dfrac{40}{8}

{\boxed{\large{\bold{x\:=5}}}}

⠀⠀⠀⠀⠀⠀⠀\mathcal{\underbrace{Verification\::- }}

L.H.S

16(3x-5) - 10(4x-8) = 40

After filling the value of x = 5

\hookrightarrow 16(3(5)-5) - 10(4(5)-8) = 40

\hookrightarrow 16(15-5) - 10(20-8) = 40

\hookrightarrow 16(10) - 10(12) = 40

\hookrightarrow\:160\:-120\:=\:40

{\boxed{\large{\bold{LHS\:=160-120\:=40}}}}

R.H.S

{\boxed{\large{\bold{RHS\:=40}}}}

Hence L.H.S = R.H.S

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