Solve the equation
2(2x+3/x-3)-25(x-3/2x+3)=5
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Let 2x+3/x-3 be y
2y-25/y=5
2y²-25=5y
2y²-5y-25=0
2y²-10y+5y-25=0
2y(y-5)+5(y-5)=0
(y-5)(2y+5)=0
y=5. y=-5/2
ksburdak:
Please solve the remaining by putting the values of y
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