solve the equation 2 by 5 x square minus x minus 3 by 5 is equals to zero by using quadratic quadratic formula
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given quadratic equation is 2x²/5-x-3/5=0
Now,D=b²-4ac
=(-1)²-4(2/5)(-3/5)
=1+24/25
=49/25
since,D>0
so,roots are real and distinct
by quadratic formula
x=-b±√D/2a
=-(-1)±√49/25/2×2/5
=1±7/5/4/5
=(5±7/5)5/4
=5±7/4
taking +ve. taking -ve
x=5+7/4. x=5-7/4
x=12/4. x=-2/4
x=3. x=-1/2
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