Math, asked by Anonymous, 1 year ago

Solve the equation.
(2+i)x^2 + (i-5)x + 2(1-i)=0

Answers

Answered by vamritaeunameun
0

Answer:

2x²+ix²+ix-5x+2-2i=0

Step-by-step explanation:

(2+i)x^2 + (i-5)x + 2(1-i)=0

2x²+ix²+ix-5x+2-2i=0



hope it helps


vamritaeunameun: toh report ker do
Anonymous: Mera ye koi help nhi kiya
Anonymous: kar diye report
Anonymous: Sirf point lo ge
vamritaeunameun: 2x²+ix²+ix-5x+2-2i=0 then 2x²+ix²-5x+ix+2-2i=0 then 2x²-5x+2= -ix²-ix+2i then (x-4)(x-1)= -i(2x+x-2) is the solution
vamritaeunameun: sorry but abb thik hai?
Anonymous: nhi abhi bhi answer nhi aaya
vamritaeunameun: kyu toh ans kya hai?
Anonymous: (1-i) aur 4-2i÷5
vamritaeunameun: ohk
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