Question

solve the equation 2-(x-3)=3x+4/x+1​

Answer 1

Answer:

$\alpha =\frac{1+\sqrt{1+16 } }{8} \\\\\beta =\frac{1-\sqrt{1+16 } }{8}$

Step-by-step explanation:

$2-(x-3)=3x+\frac{4}{x+1} \\\\2-x+3=\frac{3x(x+1)+4}{x+1}\\ \\(2-x+3)(x+1)=3x^{2}+3x+4\\ \\2x+2-x^{2}-x+3x+3=3x^{2}+3x+4\\\\4x^{2}-x-1=0\\ \\using \ formula \ x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a} \\\\x=\frac{1+-\ \sqrt{1+16 } }{2*4}\\  \\\alpha = \frac{1+\sqrt{1+16 } }{8} \\\\\beta =\frac{1-\sqrt{1+16 } }{8}$