Math, asked by lalitjoshi63, 3 months ago

solve the equation 2^x-3=4^x-1

Answers

Answered by kartik2507
1

Step-by-step explanation:

 {2}^{x - 3}  =  {4}^{x - 1}  \\  {2}^{x - 3}  =  {( {2}^{2} )}^{x - 1}  \\  {2}^{x - 3}  =  {2}^{2x - 2}  \\ base \: are \: same \: powers \: to \: be \: equated \\ x - 3 = 2x - 2 \\ x - 2x =  - 2 + 3 \\  - x = 1 \\ x =  - 1

therefore x = -1

verification

 {2}^{ - 1 - 3}  =  {4}^{ - 1 - 1}  \\  {2}^{ - 4}  =  {4}^{ - 2}   \\  {2}^{ - 4}  =  {( {2}^{2} )}^{ - 2}  \\  {2}^{ - 4}  =  {2}^{ - 4}

Hope you get your answer

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