Math, asked by swastikadubey195, 12 days ago

Solve the equation: 2^x-3 = 4^x-1​

Answers

Answered by rutujakokate6
1

Answer:

x^4 - 4x^3 + 5x^2 + 2x - 8 =0

Answered by Anonymous
36

Answer~

: \longrightarrow 2^{x-3} = 4^{x-1}

 \blue: \red \longrightarrow \ \: : 2^{x-3 }= 2^{2 \times (x-1)}

 \blue :  \   \red \longrightarrow \ \: 2^{x-3 }= 2^{2x-2}

 \orange :  \green \longrightarrow \: x - 3 = 2x - 2

 \orange :  \green \longrightarrow \: x - 2x =  - 2 + 3

 \huge \orange :  \green \longrightarrow \: {  \huge \boxed {x =  - 1}}

--------------------------

Verification:-

:  \red \longrightarrow 2^{x-3 }= 4^{x-1}

:  \red \longrightarrow \: 2^ {- 1-3} = 4^{-1 - 1}

 : \red \longrightarrow \:  - 2 =  - 2

 \bigstar \bold \green   {Here  \: LHS = RHS}

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