Question

solve the equation 2^y-3=4^y-1​

Answer 1

y = -1

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Answer 2

Answer:

y = -1

Step-by-step explanation:

2^y-3 = 4^y-1

2^y-3 = (2²)^y-1

2^y-3 = 2^2y-2

Base are equal, So

Exponent => y-3 = 2y-2

y-2y = -2+3

-y = 1

y = -1

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