Question

solve the equation !!!!!!!!!!!!!!!!!!!!​

Answer 1

Step-by-step explanation:

Lets assume the following

$\sqrt{( \frac{x - 1}{3x + 2)} } = y$

Hence given expression becomes

$y + \frac{2}{y} = 3$

${y}^{2} + 2 - 3y = 0$

Solving we get

$y = - 2 \: and \: - 1$

Now when y=-2,

$\sqrt{( \frac{x - 1}{3x + 2} )} = - 2$

Squaring

$\frac{x - 1}{3x + 2} = 4$

Solving we get,

$x = \frac{ - 9}{11}$

Similarly, when y= -1,

$x = \frac{ - 3}{2}$